docker-scripts/docker-deploy

#!/bin/bash -e

while test $# -gt 0; do
    case "$1" in
	(-h|--help) cat <<EOF
$0 [OPTIONS] FILES…

OPTIONS

  -h, --help           show this help

FILES…

  List of stack names or yaml files to deploy. There must be yaml
  files with the same name. The extension .yaml may be given or not.

DESCRIPTION

  Deploys stack from yaml files. The stack name is identical to the
  file name, but wihout path and without .yaml extendsion.

EXAMPLS

  The following calls ado the same and deploy a local yaml file:

    $0 yaml-file-name
    $0 yaml-file-name.yaml
    $0 ./yaml-file-name.yaml

  Deploy three files from three sources:

    $0 /path/to/file1/first.yaml /path/to/file2/second.yaml third

EOF
		    exit;;
	(*) break;;
    esac
    if test $# -lt 1; then
	echo "error: missing argument, try $0 --help" 1>&2
	exit 1
    fi
    shift
done

for f in $*; do
    f=${f%.yaml}
    if ! test -e ${f}.yaml; then
	echo "ERROR: no file ${f}.yaml" 1>&2
	exit 1
    fi
    echo "... deploying ${f##*/}"
    for d in $(sed -n 's,^ *source: \(/.*\),\1,p' ${f}.yaml); do
        test -e $d || mkdir -p $d
    done
    docker stack deploy --compose-file ${f}.yaml ${f##*/}
done